B
Explanation:
The reaction equation is N2O4 (l) →→ 2NO2 (g).
Drawing an enthalpy cycle reveals that ΔHfΘ (N2O4) = 2ΔHfθ (NO2) − ΔHrθ=2×33.1−85.8=−19.6kJ mol−1.
The alternative options are obtained if the wrong signs are given to the enthalpy changes in the equation and/or ΔHfθ (NO2) is not multiplied by 2.
This question is categorised as very hard, as the student must deduce the stoichiometry of the reaction, sum the enthalpy changes with the correct signs, and obtain the correct value for the unknown quantity, without the aid of a reaction equation or enthalpy cycle.