5. A reaction involving X and Y is measured and the following data is found:
| Trial | [X] (mol dm−3) | [Y] (mol dm−3) | Rate (s−1) |
| 1 | 0.10 | 0.50 | 0.20 |
| 2 | 0.20 | 0.50 | 0.40 |
| 3 | 0.20 | 0.25 | 0.40 |
What possible mechanism is consistent with the data?
C
Explanation:
Using trials 1 and 2, as [X] doubles, rate also doubles therefore first order with respect to [X].
Using trials 2 and 3, as [Y] halves, rate stays the same and so, zero order with respect to [Y].
This gives a slow step that depends on unimolecular X, and not Y.